I’m aware of anydice & looked at it but haven’t learned to program oit yet.
Also, since @tezrak.bsky.social was hesitant over trusting a machine’s answer, I was hesitant to send him towards a different machine to help him. That’s why I went towards the show my work approach.
I’m glad you are figuring it out. A quick formula is 1 - (0.70^n), where n is the number of dice. ^ means to the power of. Basically, you calculate the odds of all failure and subtract that from 100%. That gives the change of succeeding at least once.
